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Unable to link to named constructor if class has field of same name #2276
/// You can also use the [new Foo.bar] constructor.classFoo {
/// Creates with bar null.Foo() : bar =null;
/// Creates with bar 1.Foo.bar() : bar =1;
/// The bar.finalint bar;
}
The [new Foo.bar] links to the property and reports the following warning:
Activity
Fix doc TODO (#136485)