1892 United States presidential election in Rhode Island
November 8, 1892
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| Elections in Rhode Island |
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The 1892 United States presidential election in Rhode Island took place on November 8, 1892, as part of the 1892 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.
Rhode Island voted for the Republican nominee, incumbent President Benjamin Harrison, over the Democratic nominee, former President Grover Cleveland, who was running for a second, non-consecutive term. Harrison won the state by a narrow margin of 4.96%.
This was easily the closest a Democrat came to winning Rhode Island during the Republican party's 14 election win streak beginning in 1856 shortly after the formation of the party and lasting until Woodrow Wilson's 1912 win against split opposition. Indeed, it is the only time the margin was even in the single digits.
Results
[edit]| 1892 United States presidential election in Rhode Island[1] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Republican | Benjamin Harrison of Indiana (incumbent) | Whitelaw Reid of New York | 26,975 | 50.71% | 4 | 100.00% | ||
| Democratic | Grover Cleveland of New York | Adlai Ewing Stevenson I of Illinois | 24,336 | 45.75% | 0 | 0.00% | ||
| Prohibition | John Bidwell of California | James Britton Cranfill of Texas | 1,654 | 3.11% | 0 | 0.00% | ||
| Populist | James Baird Weaver of Iowa | James Gaven Field of Virginia | 228 | 0.43% | 0 | 0.00% | ||
| N/A | Others | Others | 3 | 0.01% | 0 | 0.00% | ||
| Total | 53,196 | 100.00% | 4 | 100.00% | ||||
See also
[edit]References
[edit]- ↑ "1892 Presidential General Election Results - Rhode Island". U.S. Election Atlas. Retrieved December 23, 2013.