OUTER APPLY Fundamentals: Part 2
In Part 2 of this series we learn how OUTER APPLY can be used in your queries to return data, even when there are no matches between tables.
2026-08-12
3,285 reads
In Part 2 of this series we learn how OUTER APPLY can be used in your queries to return data, even when there are no matches between tables.
2026-08-12
3,285 reads
Microsoft introduced the APPLY operator in SQL Server 2005. Similar to a JOIN, it allows correlation between two table expressions. The key difference between the JOIN and APPLY operators is when you have a table-valued expression on the right side and want to evaluate it for each row from the left table expression. Since they produce similar results, when do you choose an APPLY versus a JOIN?
2025-11-07
Learn how to unpivot data or sets of data with SQL Server queries using CROSS APPLY.
2023-11-24
2023-07-21
515 reads
2023-07-14
541 reads
This script converts hierarchical adjacency into nested json rows which contain the recursive "downlines" of each node. The table-valued function treats each row in the original adjacency as the root node in a recursive common table expression.
2019-11-24
954 reads
This script converts hierarchical adjacency into nested json rows which contain the recursive "downlines" of each node. The table-valued function treats each row in the original adjacency as the root node in a recursive common table expression.
2019-11-12 (first published: 2019-11-08)
2,173 reads
2015-10-15
1,810 reads
2012-10-01
2,536 reads
The second of a series by Paul White examining the APPLY operator. In this section learn how this operator compares with joins and about both the cross and outer options.
2012-01-13 (first published: 2010-04-19)
29,679 reads
By James Serra
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By Steve Jones
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Title pretty much says it. I want to join to a table that has...
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I have this table in a SQL Server 2025 database:
CREATE TABLE [dbo].[CustomerOrder] ( [OrderID] [int] NULL, [CustomerID] [int] NULL, [total] [money] NULL ) ON [PRIMARY] GOWhat is returned from this code? (answers are for the sum and then the count)
SELECT SUM(total) AS sum,
COUNT(total) AS count
FROM dbo.CustomerOrder;
See possible answers